Angular regex that matches a pair of words between ->

Issue

I need a regex that matches texts with one or more lines from here:

"" (empty chain)

word1->word2

word1 -> word2

succesives \r\s\t

\n

etc.
word1 and word 2 can be a combo of digits ; # or any symbol excepting \n.

I’ve proved this:

const expreg = new RegExp('([^"->"\n]->[^"->"\n])|(([^"->"\n]->[^"->"\n])\n)*');

But it also matches

word1->

second try: but it doesn’t even match hello1->hello2

((^(\s\r\t|\n|->)^(->|\n)->^(\s|\r|\t|\n|->)^(->|\n))|(^(\s|\r|\t|\n|->)^(->|\n)->^(\s|\r|\t|\n|->)^(->|\n)\n)|(\n)|([\s\r\t]+)|([\s\r\t]+\n))

Solution

You could match 1 or more word characters, and then have a repeating part matching -> followed by 1 or more word characters again.

The whole expression is optional to also match an empty string.

^(?:[^>-]+[^\S\r\n]*->[^\S\r\n]*[^>-]+)?$

See a regex demo

const expreg = /^(?:[^>-]+[^\S\r\n]*->[^\S\r\n]*[^>-]+)?$/m;
[
  "word1->word2",
  "",
  "word1  ->   word2",
  "my django db->my django db",
  "tds->dfds\nmy->computer",
  "word1->",
  "word1  ->   word2 ->word3"
].forEach(s => console.log(`${expreg.test(s)} "${s}"`));

Answered By – The fourth bird

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