Issue
For my new project i want the so modern approach of not needing to reload a page on every database request. 🙂 I want the script to query the database and create a table with the query information.
I have tried different scripts i have found on the internet. The one below was closest to my needs.
index.php
<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN' 'http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd'>
<html xmlns='http://www.w3.org/1999/xhtml'>
<head>
<title>Display Page</title>
<meta http-equiv='Content-Type' content='text/html; charset=utf-8' />
<script language='JavaScript' type='text/javascript' src='https://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js'></script>
</head>
<body>
<button type='button' name='getdata' id='getdata'>Get Data.</button>
<div id='result_table'>
</div>
<script type='text/javascript' language='javascript'>
$('#getdata').click(function(){
$.ajax({
url: 'getdata.php',
type:'POST',
dataType: 'json',
success: function(output_string){
$('#result_table').append(output_string);
} // End of success function of ajax form
}); // End of ajax call
});
</script>
</body>
</html>
getdata.php
<?php
include('conn.inc.php');
//Query of facebook database
$facebook = mysql_query('SELECT * FROM users')
or die(mysql_error());
//Output results
if(!$facebook)
{
mysql_close();
echo json_encode('There was an error running the query: ' . mysql_error());
}
elseif(!mysql_num_rows($facebook))
{
mysql_close();
echo json_encode('No results returned');
}
else
{
$output_string = '';
$output_string .= '<table border="1">';
while($row = mysql_fetch_assoc($facebook))
{
$output_string .= '<tr>';
foreach($row as $value)
{
$output_string .= '<td>{$value}</td>';
}
$output_string .= '</tr>';
}
$output_string .= '</table>';
}
mysql_close();
// This echo for jquery
echo json_encode($output_string);
?>
But i only get a table with a bunch of {$value} inside the table. I’ve tried with only $value but got a bunch of zeros.
I tried a simple script
$query = "SELECT users_name, users_password FROM users WHERE users_name = 'name'";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result);
echo $row['users_name'];
And then i get som results but with this script i have to refresh the page on every search. To be clear i want to be able to create a table with the information from a mysql database and display it on screen with reloading the page.
Any ideas?
Solution
You should just use $value instead of {$value}. You don’t need another foreach loop inside the while loop.
$output_string = '';
$output_string .= '<table border="1">';
while($row = mysql_fetch_assoc($facebook))
{
$output_string .= '<tr>';
$output_string .= '<td>'.$row['Your table column name here'].'</td>';
$output_string .= '</tr>';
}
$output_string .= '</table>';
Answered By – Joseph
This Answer collected from stackoverflow, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0