file_get_contents in php returns empty string


SQL Tablemy loadtable function
If i delete the button in the table . through the id the sql database didnt get delete

I have searched a lot about this related article . . I couldn’t find the solution
passing my id in http delete request. when I have var_dump the variable its giving empty string.
It didn’t give error it is just gave data deleted correctly message. but didn’t get deleted

<tr ng-repeat="x in dated">
<td><button name="btn" value="Update" ng-click="updatefn(x.Id,x.Name,x.Phone,x.Status)">Update</button></td>
<td><button name="btn" value="Delete" ng-click="deletefn(x.Id)">Delete</button></td>


  url:'select.php' ,
  method: 'GET', 

url: 'delete.php',
headers: {
        'Content-type': 'application/json;charset=utf-8' }

$data = json_decode(file_get_contents("php://input")); 
    echo 'This line is printed, because the $var is null.';
var_dump($data);//empty string
 if(count(array($data)) > 0)  
 $id_del = $data->send_id;
 $query = "DELETE FROM society_tour WHERE id='$id_del'";  
if(mysqli_query($connect, $query))  
echo 'Data Deleted correctly';  
  echo 'Error';

Debugging info:

Warning provided by PHP:

Warning: Attempt to read property "send_id" on string in
C:\xampp\htdocs\delete.php on line 12

Console log results:

console.log(id) // 123
console.log(typeof(id)// string


You’re literally sending "123" by itself to the server. That isn’t JSON, and it isn’t an object, it’s just a plain string.

So I suggest

  1. remove headers: { 'Content-type': 'application/json;charset=utf-8' } from the $http options,

  2. change $data = json_decode(file_get_contents("php://input")); to just $id_del = file_get_contents("php://input");

  3. remove $id_del = $data->send_id;

  4. change if(is_null($data)){ to if(is_null($id_del)){ and change var_dump($data);//empty string if(count(array($data)) > 0) { to var_dump($id_del);//empty string if(!empty($id_del) {

This will make PHP read just the plain string and use that as the ID, without attempting to decode it as JSON or extract values from within it.

Answered By – ADyson

This Answer collected from stackoverflow, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0

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