I need a countdown timer in python but without skipping line.
from time import sleep for c in range (4,0,-1): print(c) sleep(1)
this code makes the countdown by jumping the lines
print('3') print('2') print('1')
I need that in the same line show first 3, then 2, last 1.
print('3,' + sleep(1) + '2,' + sleep(1) + '1.')
If you want delete previous number in console,
you can do like
from time import sleep import os for i in range(4, 0, -1): os.system("cls") print(i) sleep(1)
or you can use end parameter in print function.
from time import sleep for i in range(4, 0, -1): print(i, end = '\r') sleep(1)
Answered By – SaGwa