Issue
I have a listView
and I am showing students attendance
for each subject, I am parsing JSON
till secondlast
place for that. For that, in get count I did return attendanceBeanList.size()-1
. See below code.
I have done this:
private List<TotalAttendance_Bean> attendanceBeanList;
public TotalAttendanceAdapter(Activity activity, List<TotalAttendance_Bean> attendanceBeanList)
{
super();
this.activity = activity;
this.attendanceBeanList = attendanceBeanList;
}
@Override
public int getCount() {
return attendanceBeanList.size()-1;
}
Now when I am going to get last object I am stuck. I have to get Total attendance for every student. For that I have to get Last Object from below JSONArray
.
This is my JSON:
[
{
"subject_name": "English-I",
"total_classes": "2",
"total_attended": "2",
"percentage": "100"
},
{
"subject_name": "English-I",
"total_classes": "2",
"total_attended": "2",
"percentage": "100"
},
{
"subject_name": "English-I",
"total_classes": "2",
"total_attended": "2",
"percentage": "100"
},
{
"subject_name": "English-I",
"total_classes": "2",
"total_attended": "2",
"percentage": "100"
},
{
"total_attendance": 90%
}
]
This is my XML.
In this layout I am showing Every Subject Attendance in List View, and I have to show Total percentage in TextView in Blue Colour.
Solution
You can fetch your total_attendance
after parsing all students
records
JSONArray obj = new JSONArray(yourStringResponse);
// get the last object
JSONObject tot_obj = obj.getJSONObject(obj.length()-1);
// get String from last object
String tot_str = tot_obj.optString("total_attendance");
Note : optString
will convert your data to String
otherwise it will give an empty string
like ""
.
Now you can display the data in your Activity
‘s TextView
like
yourTextView.setText(tot_str);
you can pass your tot_str
to Adapter
if you need
public TotalAttendanceAdapter(Activity activity
, List<TotalAttendance_Bean> attendanceBeanList
, String tot)
{
super();
this.activity = activity;
this.attendanceBeanList = attendanceBeanList;
this.tot = tot;
}
Answered By – Pavneet_Singh
This Answer collected from stackoverflow, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0