How to return elements of an array with the highest values?

Issue

In my code I have two elements which has the same age "Joe"=>"43" and "Rob"=>"43" .

My code output is:

Joe

I want to output:

Joe and Rob

Because they has the highest value.

This is my code:

<?php
    $cur = 1;

    $age = array("Peter" => "35", "Ben" => "37", "Joe" => "43", "Rob" => "43");
    $new_array = array();
    arsort($age);
    $new_array = $age;
    $key = array_search(max($new_array), $new_array);

    while ($cur > 0) {
        echo $key;
        $cur--;
    }
?>

Solution

I’d change the keys and values in the array, then sort by key and return the values of the first key:

$ages = array("Peter" => "35", "Ben" => "37", "Joe" => "43", "Rob" => "43");
$new = array();

foreach ($ages as $name => $age) {
  $new[$age][] = $name;
}

uksort($new, function($ka, $kb) { return $kb - $ka; }); // or just krsort($new);
$new = array_values($new)[0]; // <- to use this you have to have at least PHP 5.4

// if you have PHP < 5.4 you can simply do it in two steps:
// $new = array_values($new);
// $new = $new[0];

See it in action!

EDIT: even simpler!

$ages = array("Peter" => "35", "Ben" => "37", "Joe" => "43", "Rob" => "43");
$max = max($ages);
$new = array_keys(array_filter($ages, function ($age) use ($max) { return $age == $max; }));

Answered By – Matteo Tassinari

This Answer collected from stackoverflow, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0

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