ng-if to hide/show row when value =0


The table has columns – ID, PASSED, FAILED and there is a checkbox -show students with no FAILURES

I can’t figure out how to use angular ng-if to bind the checkbox with the table. So if the user checks the checkbox , it should show all rows else only students with no failures. I’m new to angularJS 😐

   <td><span class="CheckBox"><input type="checkbox" value="">Show Students with No Failures</span></td>
<tbody >
   <!--display none-->
   <tr ng-repeat="t in table">
      <td colspan="1" ng-hide='t.Failed===0'>{{}}</td>
      <td colspan="1" ng-hide='t.Failed===0'>{{t.Total}</td>
      <td colspan="1" ng-hide='t.Failed===0'>{{t.Passed}}</td>
      <td colspan="1" ng-hide='t.Failed===0'>{{t.Failed}}</td>


Added a implementation of what you are trying to accomplish.

Using a ng-repeatin combination with a filter.



<div id="app" ng-app="myApp" ng-controller="myCtrl">

  Only passes students?
  <input type="checkbox" ng-init="passes = true" ng-model="passes">
  <br/> Not passed student students?
  <input type="checkbox" checked ng-init="fails = true" ng-model="fails">
  <table cellspacing="0" cellpadding="0">
      <tr class="days">
        <th>Student name</th>
      <tr ng-repeat="student in studentData | filter: studentFilter">
        <td>{{ }}</td>
        <td>{{ student.fails }}</td>
          {{ (student.fails <=0 ) ? 'YES' : 'NO' }} </td>



var app = angular.module('myApp', [])

app.controller('myCtrl', function($scope) {

  $scope.studentFilter = function (item) { 
        if($scope.passes && $scope.fails) return item;
      if($scope.passes && item.fails <= 0) return item;
      if($scope.fails && item.fails > 0) return item;

  $scope.studentData = [{
    id: 1,
    name: 'Nabil',
    fails: 1
  }, {
    id: 2,
    name: 'Daan',
    fails: 0
  }, {
    id: 3,
    name: 'Walter',
    fails: 2
  }, {
    id: 4,
    name: 'Magaly',
    fails: 0
  }, {
    id: 5,
    name: 'Steven',
    fails: 2
  }, {
    id: 6,
    name: 'Bill',
    fails: 0

Answered By – daan.desmedt

This Answer collected from stackoverflow, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0

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