(This question for testing) Find tuple with 3 elements in list by using tuple with 2 elements

Issue

I am using Python. Assume that I have a list of tuples, A, where each tuple, a, contains 3 elements e.g. ('z', 1, 2) and I also have a tuple with 2 element, t, like (2, 3), I want to search for first element of a e.g. 'z' that the second element and the third element match with the first element and the second element of t consecutively.

For example,

A = [('a', 1, 2), ('b', 2, 4), ('c', 2, 1), ('d', 1, 3), ('e', 1, 2)]
t = (1, 2)

Expected Output,

'a'

Thank you in advance.

Solution

def func(A,t):
    for x,y in enumerate(A):
        if t==(A[x][1],A[x][2]):
            return A[x][0]



A = [('a', 1, 2), ('b', 2, 4), ('c', 2, 1), ('d', 1, 3), ('e', 1, 2)]
t = (1,2)

result = func(A,t)
print(result)

Answered By – Bolshoi Booze

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