Using Google Chrome in Selenium VBA (Installation Steps)


I am having problems even setting up Selenium for VBA. I have been reading online on what to do, download the selenium ( add extension and etc. However, I am still struggling to get it to work.

Even writing a simple code like the following which I have found online:

Public Sub Demo()
    Dim d As WebDriver
    Set d = New ChromeDriver
    Const URL = ""

    With d
        .Start "Chrome"
        .get URL
        .FindElementById("lst-ib").SendKeys "Selenium basic GitHub"
         .FindElementsByTag("form")(1).FindElementByCss("input[value='Google Search']").Click
    End With
End Sub

Gives me an Automation error.

I would like to use google chrome in the same way as internet explorer.
I would appreciate any help with setting up selenium , and I know my question can be seen as silly.


First of all, go to control panel and uninstall previous installation of selenium and then follow the steps
1- Download the latest version of chrome and make sure of the version of Chrome from Help >> About Google Chrome. You would see something like that Version 75.0.3770.142 (Official Build) (32-bit)

2- Download the latest version from the LINK

3- Download the chromedriver from the follwoing LINK
Make sure of the version that suits your chrome version
As for the Google Chrome version I posted the most suitable version of chromedriver is ChromeDriver 75.0.3770.140

  1. Now setup SeleniumBasic >> After setup unzip the chromedriver file and copy the chromedriver.exe to the path of selenium
    Here’s two possibilties: First >> C:\Program Files\SeleniumBasic
    Second >> C:\Users\%username%\AppData\Local\SeleniumBasic
    Copy the chromedriver.exe to the SeleniumBasic path

  2. Open new blank excel file >> Press Alt + F11 (Visual Basic Editor) >> Tools >> References >> Selenium Type Library

  3. Insert new module and paste the following code to test

Sub Test()
    Dim bot         As New WebDriver
    bot.Start "chrome", ""
    bot.Get "/"
End Sub

Answered By – YasserKhalil

This Answer collected from stackoverflow, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0

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