Using Selenium to get image src inside of a link


I’m trying to get some info from this page using Selenium:’-wolf?came_from=253&utm_medium=web&utm_source=city_page&utm_campaign=event

I want to get the src of the image on the right side of page.

enter image description here

Here’s the page inspector – the src tag I’m trying to get is circled:

enter image description here

I need to access the src without referencing any explicit div names, so what I want to do is find the href instance which contains the image, and then search for the image inside of the a tag.

Here’s my code, which fails to retrieve anything (printing find_src prints nothing) :

find_src = driver.find_element_by_css_selector('a[href^=""]//img').get_attribute("src")

What am I doing wrong here?


Please retry by replacing your css selector expression with this one: "a[href^=’’] img". So, your rectified code will be:

find_src = driver.find_element_by_css_selector("a[href^=''] img").get_attribute("src")

If we want to select a descendant element using CSS selectors, space " " is used but in your CSS selector expression, "//" is there. For more information, kindly refer this link:

Answered By – Rahul

This Answer collected from stackoverflow, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0

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